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SSC (Marathi Semi-English) १० वीं कक्षा - Maharashtra State Board Question Bank Solutions

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Show that the point (0, 9) is equidistant from the points (– 4, 1) and (4, 1)

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Show that the points (0, –1), (8, 3), (6, 7) and (– 2, 3) are vertices of a rectangle.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

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Show that the points (2, 0), (– 2, 0) and (0, 2) are vertices of a triangle. State the type of triangle with reason

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Show that A(1, 2), (1, 6), C(1 + 2 `sqrt(3)`, 4) are vertices of a equilateral triangle

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Seg OA is the radius of a circle with centre O. The coordinates of point A is (0, 2) then decide whether the point B(1, 2) is on the circle?

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Using distance formula decide whether the points (4, 3), (5, 1), and (1, 9) are collinear or not.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

If a and b are natural numbers and a > b If (a2 + b2), (a2 – b2) and 2ab are the sides of the triangle, then prove that the triangle is right-angled. Find out two Pythagorean triplets by taking suitable values of a and b.

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

Prove that, The areas of two triangles with the same height are in proportion to their corresponding bases. To prove this theorem start as follows:

  1. Draw two triangles, give the names of all points, and show heights.
  2. Write 'Given' and 'To prove' from the figure drawn.
[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Find distance between points P(– 5, – 7) and Q(0, 3).

By distance formula,

PQ = `sqrt(square + (y_2 - y_1)^2`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(square + square)`

= `sqrt(125)`

= `5sqrt(5)`

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

If m and n are real numbers and m > n, if m2 + n2, m2 – n2 and 2 mn are the sides of the triangle, then prove that the triangle is right-angled. (Use the converse of the Pythagoras theorem). Find out two Pythagorian triplets using convenient values of m and n.

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

If ΔABC ∼ ΔDEF, length of side AB is 9 cm and length of side DE is 12 cm, then find the ratio of their corresponding areas.

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

What is the distance of the point (– 5, 4) from the origin?

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

In the figure, PQ ⊥ BC, AD ⊥ BC. To find the ratio of A(ΔPQB) and A(ΔPBC), complete the following activity.


Given: PQ ⊥ BC, AD ⊥ BC

Now, A(ΔPQB)  = `1/2 xx square xx square`

A(ΔPBC)  = `1/2 xx square xx square`

Therefore, 

`(A(ΔPQB))/(A(ΔPBC)) = (1/2 xx square xx square)/(1/2 xx square xx square)`

= `square/square`

[1] Similarity
Chapter: [1] Similarity
Concept: undefined >> undefined

Find the value of y, if the points A(3, 4), B(6, y) and C(7, 8) are collinear.

[3] Circle
Chapter: [3] Circle
Concept: undefined >> undefined

Draw a line segment AB of length 10 cm and divide it internally in the ratio of 2:5 Justify the division of line segment AB.

[4] Geometric Constructions
Chapter: [4] Geometric Constructions
Concept: undefined >> undefined

Find the distance between the points O(0, 0) and P(3, 4).

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

Show that points A(–1, –1), B(0, 1), C(1, 3) are collinear.

[5] Co-ordinate Geometry
Chapter: [5] Co-ordinate Geometry
Concept: undefined >> undefined

In the following figure, in ΔABC, ∠B = 90°, ∠C = 60°, ∠A = 30°, AC = 18 cm. Find BC.

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

In the given figure. Find RP and PS using the information given in ∆PSR.

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined

In the given figure, ∆PQR is an equilateral triangle. Point S is on seg QR such that QS = n\[\frac{1}{3}\] QR.

Prove that: 9 PS= 7 PQ2

[2] Pythagoras Theorem
Chapter: [2] Pythagoras Theorem
Concept: undefined >> undefined
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Maharashtra State Board SSC (Marathi Semi-English) १० वीं कक्षा Question Bank Solutions
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Question Bank Solutions for Maharashtra State Board SSC (Marathi Semi-English) १० वीं कक्षा Hindi (Second/Third Language) [हिंदी (दूसरी/तीसरी भाषा)]
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Question Bank Solutions for Maharashtra State Board SSC (Marathi Semi-English) १० वीं कक्षा Sanskrit (Second Language) [संस्कृत (द्वितीय भाषा)]
Question Bank Solutions for Maharashtra State Board SSC (Marathi Semi-English) १० वीं कक्षा Sanskrit - Composite [संस्कृत - संयुक्त (द्वितीय भाषा)]
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