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Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

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Mathematics
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Every invertible function is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

In the interval (1, 2), function f(x) = 2 | x − 1 | + 3 | x − 2 | is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

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If the function f(x) = cos |x| − 2ax + b increases along the entire number scale, then

 

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

The function \[f\left( x \right) = \frac{x}{1 + \left| x \right|}\] is 

 

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

The function \[f\left( x \right) = \frac{\lambda \sin x + 2 \cos x}{\sin x + \cos x}\] is increasing, if

 

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Function f(x) = ax is increasing on R, if

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Function f(x) = loga x is increasing on R, if

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Let ϕ(x) = f(x) + f(2a − x) and f"(x) > 0 for all x ∈ [0, a]. Then, ϕ (x)

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

If the function f(x) = x2 − kx + 5 is increasing on [2, 4], then

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

The function f(x) = −x/2 + sin x defined on [−π/3, π/3] is

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Find the equation of the line passing through the point (1, 2, −4) and parallel to the line \[\frac{x - 3}{4} = \frac{y - 5}{2} = \frac{z + 1}{3} .\] 

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

If the function f(x) = x3 − 9kx2 + 27x + 30 is increasing on R, then

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Find the equations of the line passing through the point (−1, 2, 1) and parallel to the line  \[\frac{2x - 1}{4} = \frac{3y + 5}{2} = \frac{2 - z}{3} .\]

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

The function f(x) = x9 + 3x7 + 64 is increasing on

[6] Applications of Derivatives
Chapter: [6] Applications of Derivatives
Concept: undefined >> undefined

Find the equation of the line passing through the point (2, −1, 3) and parallel to the line  \[\overrightarrow{r} = \left( \hat{i} - 2 \hat{j} + \hat{k} \right) + \lambda\left( 2 \hat{i} + 3 \hat{j} - 5 \hat{k} \right) .\]

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the equations of the line passing through the point (2, 1, 3) and perpendicular to the lines  \[\frac{x - 1}{1} = \frac{y - 2}{2} = \frac{z - 3}{3} \text{  and  } \frac{x}{- 3} = \frac{y}{2} = \frac{z}{5}\]

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the equation of the line passing through the point  \[\hat{i}  + \hat{j}  - 3 \hat{k} \] and perpendicular to the lines  \[\overrightarrow{r} = \hat{i}  + \lambda\left( 2 \hat{i} + \hat{j}  - 3 \hat{k}  \right) \text { and }  \overrightarrow{r} = \left( 2 \hat{i}  + \hat{j}  - \hat{ k}  \right) + \mu\left( \hat{i}  + \hat{j}  + \hat{k}  \right) .\]

  

 

 

 

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Find the equation of the line passing through the point (1, −1, 1) and perpendicular to the lines joining the points (4, 3, 2), (1, −1, 0) and (1, 2, −1), (2, 1, 1).

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Determine the equations of the line passing through the point (1, 2, −4) and perpendicular to the two lines \[\frac{x - 8}{8} = \frac{y + 9}{- 16} = \frac{z - 10}{7} \text{    and    } \frac{x - 15}{3} = \frac{y - 29}{8} = \frac{z - 5}{- 5}\]

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined

Show that the lines \[\frac{x - 5}{7} = \frac{y + 2}{- 5} = \frac{z}{1} \text{ and } \frac{x}{1} = \frac{y}{2} = \frac{z}{3}\] are perpendicular to each other.

[11] Three - Dimensional Geometry
Chapter: [11] Three - Dimensional Geometry
Concept: undefined >> undefined
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