Secondary School (English Medium) (5 to 8) कक्षा ८ - CBSE Question Bank Solutions

Find x.

`(- 1/7)^-5 ÷ (- 1/7)^-7 = (-7)^x`

Find x.

`(2/5)^(2x + 6) xx (2/5)^3 = (2/5)^(x + 2)`

Find x.

2^x + 2^x + 2^x = 192

Find x.

`((-6)/7)^(x - 7) = 1`

Find x.

2^3x = 8^{2x + 1}

Find x.

5^x + 5^{x – 1} = 750

If a = – 1, b = 2, then find the value of the following:

a^b + b^a 

If a = – 1, b = 2, then find the value of the following:

a^b – b^a 

If a = – 1, b = 2, then find the value of the following:

a^b × b^a 

If a = – 1, b = 2, then find the value of the following:

a^b ÷ b^a 

Simplify:

`[(1/2)^2 - (1/4)^3]^-1 xx 2^-3`

Simplify:

`[(4/3)^-2 - (3/4)^2]^((-2))`

Simplify:

`(4/13)^4 xx (13/7)^2 xx (7/4)^3`

Simplify:

`(1/5)^45 xx (1/5)^-60 - (1/5)^(+28) xx (1/5)^-43`

Simplify:

`((9)^3 xx 27 xx t^4)/((3)^-2 xx (3)^4 xx t^2)`

Simplify:

`((3^-2)^2 xx (5^2)^-3 xx (t^-3)^2)/((3^-2)^5 xx (5^3)^-2 xx (t^-4)^3`

If marked price of an article is Rs 1,200 and the discount is 12% then the selling price of the article is ______.

If 90% of x is 315 km, then the value of x is ______.

To gain 25% after allowing a discount of 10%, the shopkeeper must mark the price of the article which costs him Rs 360 as ______.

If a % is the discount per cent on a marked price x, then discount is ______.