Advertisements
Advertisements
प्रश्न
Find x.
`(- 1/7)^-5 ÷ (- 1/7)^-7 = (-7)^x`
Advertisements
उत्तर
Using law of exponents,
am ÷ an = (a)m – n ...[∵ a is non-zero integer]
Then, `(- 1/7)^(-5 + 7) = (-7)^x`
⇒ `(- 1/7)^2 = (- 7)^x`
⇒ (–7)–2 = (–7)x
On comparing powers of (–7), we get
x = –2
APPEARS IN
संबंधित प्रश्न
Find the value of `1/(3^(-2))`.
Simplify and write the answer in the exponential form.
If x be any non-zero integer, then x–1 is equal to ______.
By solving (60 – 70) × (60 + 70) we get ______.
The value of [1–2 + 2–2 + 3–2 ] × 62 is ______.
Find the value of x so that (2–1 + 4–1 + 6–1 + 8–1)x = 1
By what number should (–15)–1 be divided so that quotient may be equal to (–15)–1?
A new born bear weighs 4 kg. How many kilograms might a five year old bear weigh if its weight increases by the power of 2 in 5 years?
Find x.
5x + 5x – 1 = 750
Simplify:
`(4/13)^4 xx (13/7)^2 xx (7/4)^3`
