Science (English Medium) कक्षा १२ - CBSE Question Bank Solutions for Chemistry

Which of the following mixture is(are) called solution?

(i) water + ammonia

(ii) water + acetone

(iii) acetone + alcohol

(iv) hexane + water

Which of the following statement is incorrect for group 15 elements?

What causes nitrogen to be chemically inert?

Nitrogen dioxide cannot be obtained by heating:

When two halogen atoms are attached to the same carbon atom then it is:

Which one of the following is non-crystalline or amorphous?

m-Xylene reacts with Br₂ in presence of FeBr₃, what are products formed:

Amorphous solids are ______.

O-hydroxy benzyl alcohol when reacted with PCl₃ gives the product as ______. (IUPAC name)

Which of the following is true about the value of refractive index of quartz glass?

Amorphous solid can also be called:

(i) pseudo solids

(ii) true solids

(iii) supercooled liquids

(iv) supercooled solids

Which of the following features are not shown by quartz glass?

(i) This is a crystalline solid.

(ii) Refractive index is same in all the directions.

(iii) This has definite heat of fusion.

(iv) This is also called super cooled liquid.

Under which situations can an amorphous substance change to crystalline form?

Electrode potential for Mg electrode varies according to the equation

`E_(Mg^(2+)  |  Mg) = E_(Mg^(2+)  |  Mg)^Θ - 0.059/2 log  1/([Mg^(2+)])`. The graph of `E_(Mg^(2+)  |  Mg)` vs `log [Mg^(2+)]` is ______.

Which of the following statement is correct?

Which of the following statement is not correct about an inert electrode in a cell?

An electrochemical cell can behave like an electrolytic cell when ______.

Use the data given in below find out which option the order of reducing power is correct.

`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖`= 1.33 V `"E"_("Cl"_2//"Cl"^-)^⊖` = 1.36 V

`"E"_("MnO"_4^-//"Mn"^(2+))^⊖` = 1.51 V `"E"_("Cr"^(3+)//"Cr")^⊖` = - 0.74 V

Use the data given in below find out the most stable ion in its reduced form.

`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖`= 1.33 V `"E"_("Cl"_2//"Cl"^-)^⊖` = 1.36 V

`"E"_("MnO"_4^-//"Mn"^(2+))^⊖` = 1.51 V `"E"_("Cr"^(3+)//"Cr")^⊖` = - 0.74 V

Use the data given in below find out the most stable oxidised species.

`E^0 (Cr_2O_1^(2-))/(Cr_(3+))` = 1.33 V   `E^0 (Cl_2)/(Cl^-)` = 1.36 V

`E^0 (MnO_4^-)/(MN^(2+))` = 1.51 V   `E^0 (Cr^(3+))/(Cr)` = – 0.74 V