Please select a subject first
Advertisements
Advertisements
Find the geometric means of the following pairs of number:
−8 and −2
Concept: undefined >> undefined
The sum of two numbers is 6 times their geometric means, show that the numbers are in the ratio `(3+2sqrt2):(3-2sqrt2)`.
Concept: undefined >> undefined
Advertisements
If the fifth term of a G.P. is 2, then write the product of its 9 terms.
Concept: undefined >> undefined
If (p + q)th and (p − q)th terms of a G.P. are m and n respectively, then write is pth term.
Concept: undefined >> undefined
If logxa, ax/2 and logb x are in G.P., then write the value of x.
Concept: undefined >> undefined
If the sum of an infinite decreasing G.P. is 3 and the sum of the squares of its term is \[\frac{9}{2}\], then write its first term and common difference.
Concept: undefined >> undefined
\[\lim_{x \to 1} \frac{x^2 + 1}{x + 1}\]
Concept: undefined >> undefined
\[\lim_{x \to 0} \frac{2 x^2 + 3x + 4}{x^2 + 3x + 2}\]
Concept: undefined >> undefined
\[\lim_{x \to 3} \frac{\sqrt{2x + 3}}{x + 3}\]
Concept: undefined >> undefined
\[\lim_{x \to 1} \frac{\sqrt{x + 8}}{\sqrt{x}}\]
Concept: undefined >> undefined
\[\lim_{x \to a} \frac{\sqrt{x} + \sqrt{a}}{x + a}\]
Concept: undefined >> undefined
\[\lim_{x \to 1} \frac{1 + \left( x - 1 \right)^2}{1 + x^2}\]
Concept: undefined >> undefined
\[\lim_{x \to 0} \frac{x^{2/3} - 9}{x - 27}\]
Concept: undefined >> undefined
\[\lim_{x \to 0} 9\]
Concept: undefined >> undefined
\[\lim_{x \to 2} \left( 3 - x \right)\]
Concept: undefined >> undefined
\[\lim_{x \to - 1}{\left( 4 x^2 + 2 \right)}\]
Concept: undefined >> undefined
\[\lim_{x \to - 1} \frac{x^3 - 3x + 1}{x - 1}\]
Concept: undefined >> undefined
\[\lim_{x \to 0} \frac{3x + 1}{x + 3}\]
Concept: undefined >> undefined
\[\lim_{x \to 3} \frac{x^2 - 9}{x + 2}\]
Concept: undefined >> undefined
\[\lim_{x \to 0} \frac{ax + b}{cx + d}, d \neq 0\]
Concept: undefined >> undefined
