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SSC (English Medium) १० वीं कक्षा - Maharashtra State Board Important Questions for Geometry Mathematics 2

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Geometry Mathematics 2
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Prove that sin6θ + cos6θ = 1 – 3 sin2θ. cos2θ.

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Prove that:

sec2θ + cosec2θ = sec2θ x cosec2θ

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Eliminate θ, if
x = 3 cosec θ + 4 cot θ
y = 4 cosec θ – 3 cot θ

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Prove that `(sinθ - cosθ + 1)/(sinθ + cosθ - 1) = 1/(secθ - tanθ)`

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:

sin θ × cosec θ = ______

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Prove that `sqrt((1 + sin A)/(1 - sin A))` = sec A + tan A.

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

The radii of the ends of a frustum are 14 cm and 6 cm respectively and its height is 6 cm. Find its curved surface area.

Appears in 2 question papers
Chapter: [7] Mensuration
Concept: Frustum of a Cone

The radius of a circle is 10 cm. The measure of an arc of the circle is 54°. Find the area of the sector associated with the arc. (\[\pi\]= 3.14 )

Appears in 2 question papers
Chapter: [7] Mensuration
Concept: Length of an Arc

In the given figure, square ABCD is inscribed in the sector A - PCQ. The radius of sector C - BXD is 20 cm. Complete the following activity to find the area of shaded region 

Appears in 2 question papers
Chapter: [7] Mensuration
Concept: Length of an Arc

The ratio of the areas of two triangles with the common base is 14 : 9. Height of the larger triangle is 7 cm, then find the corresponding height of the smaller triangle.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

The ratio of the areas of two triangles with common base is 6:5. Height of the larger triangle of 9 cm, then find the corresponding height of the smaller triangle.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find `("A"(∆"ABC"))/("A"(∆"ADB"))`

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In adjoining figure, PQ ⊥ BC, AD ⊥ BC then find following ratios.

  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
  4. `("A"(∆"ADC"))/("A"(∆"PQC"))`
Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In ∆PQR, PM = 15, PQ = 25 PR = 20, NR = 8. State whether line NM is parallel to side RQ. Give reason. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of Three Parallel Lines and Their Transversals

In ∆MNP, NQ is a bisector of ∠N. If MN = 5, PN = 7 MQ = 2.5 then find QP. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In trapezium ABCD, side AB || side PQ || side DC, AP = 15, PD = 12, QC = 14, Find BQ. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of Three Parallel Lines and Their Transversals

Find QP using given information in the figure.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In the given figure, if AB || CD || FE then find x and AE. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

 In trapezium PQRS, side PQ || side SR, AR = 5AP, AS = 5AQ then prove that, SR = 5PQ 

 

 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles
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Maharashtra State Board SSC (English Medium) १० वीं कक्षा Important Questions
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Algebra Mathematics 1
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा English
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Geography
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Geometry Mathematics 2
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Hindi
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Hindi (Second/Third Language) [हिंदी (दूसरी/तीसरी भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Hindi - Composite [हिंदी - संयुक्त]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा History and Political Science
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Marathi (Second Language) [मराठी (द्वितीय भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Marathi - Composite [[मराठी - संयुक्त (द्वितीय भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Sanskrit (Second Language) [संस्कृत (द्वितीय भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Sanskrit - Composite [संस्कृत - संयुक्त (द्वितीय भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Science and Technology 1
Important Questions for Maharashtra State Board SSC (English Medium) १० वीं कक्षा Science and Technology 2
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