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प्रश्न
Write the value of `(cot^2 theta - 1/(sin^2 theta))`.
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उत्तर
`(cot^2 theta - 1/ sin^2 theta)`
=`(cot^2 theta - cosec^2 theta )`
=-1
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Activity:
L.H.S = `square`
= `cos^2theta xx square .....[1 + tan^2theta = square]`
= `(cos theta xx square)^2`
= 12
= 1
= R.H.S
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