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प्रश्न
Write the zeros of the polynomial f(x) = x2 – x – 6.
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उत्तर
f(x) = x2 – x – 6
= x2 – 3x + 2x – 6
= x(x – 3) + 2(x – 3)
= (x – 3) (x + 2)
f(x) = 0 ⇒ (x – 3) (x + 2) = 0
⇒ (x – 3) = 0 or (x + 2) = 0
⇒ x = 3 or x = –2
So, the zeroes of f(x) are 3 and –2.
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