Advertisements
Advertisements
प्रश्न
Find the value of k such that the polynomial x2 − (k + 6)x + 2(2k −1) has sum of its zeros equal to half of their product.
Advertisements
उत्तर
Given polynomial is x2 - (k + 6) x + 2 (2k – 1)
Here
a = 1, b = - (k + 6), c = 2 (2k – 1)
Given that,
Sum of zeroes = `(1)/(2)` product of zeroes
⇒ `[-[-("k"+6)]]/(1) = (1)/(2) xx (2(2"k" - 1))/(1)`
⇒ `"k" + 6 = 2"k" - 1`
⇒ `6 + 1 = 2"k" - "k"`
⇒ `"k" = 7`
APPEARS IN
संबंधित प्रश्न
The graphs of y = p(x) are given in following figure, for some polynomials p(x). Find the number of zeroes of p(x).
Find the zeroes of the quadratic polynomial `f(x) = 5x^2 ˗ 4 ˗ 8x` and verify the relationship between the zeroes and coefficients of the given polynomial.
If one zero of the polynomial `x^2-4x+1 is (2+sqrt3)` , write the other zero.
If -2 is a zero of the polynomial `3x^2 + 4x + 2k` then find the value of k.
If ∝ and β are the zeros of the polynomial f(x) = `6x^2 + x - 2 `find the value of `(∝/β+∝/β) `
If the zeroes of the quadratic polynomial x2 + (a + 1) x + b are 2 and –3, then ______.
Given that one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is zero, the product of the other two zeroes is ______.
If the zeroes of the quadratic polynomial ax² + bx + c, c # 0 are equal, then ______.
If one of the zeroes of the quadratic polynomial (k -1)x² + kx + 1 the value of k is ______.
If the graph of a polynomial intersects the x-axis at exactly two points, it need not be a quadratic polynomial.
