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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Write structures of different dihalogen derivatives of propane.

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प्रश्न

Write structures of different dihalogen derivatives of propane.

रासायनिक समीकरण/संरचनाएँ
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उत्तर १

Four isomeric dihalogen derivatives of propane (CH3CH2CH3) are possible.

\[\ce{\underset{1, 3-dibromopropane}{BrCH2 - CH2 - CH2Br}}\]

\[\begin{array}{cc}
\ce{BrCH2 - CH - CH3}\\
\phantom{.}|\\
\phantom{...}\ce{\underset{1, 2-dibromopropane}{Br}}
\end{array}\]

\[\begin{array}{cc}
\ce{Br - CH - CH2 - CH3}\\
|\phantom{................}\\
\ce{\underset{1, 1-dibromopropane}{Br}}\phantom{..............}
\end{array}\]

\[\begin{array}{cc}
\ce{CH3 - C - CH3}\\
/\phantom{.}\backslash\\
\phantom{..}\ce{\underset{2, 2-dibromopropane}{Br\phantom{..}Br}}
\end{array}\]

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उत्तर २

The structures of all possible dihalogen derivatives of propane are:

\[\ce{\underset{1, 3-dihalopropane}{X - CH2 - CH2 - CH2 - X}}\]

\[\begin{array}{cc}
\ce{X}\phantom{..........}\\
|\phantom{..........}\\
\ce{\underset{1, 2-dihalopropane}{H3C - CH - CH2 - X}}\
\end{array}\]

\[\begin{array}{cc}
\ce{X}\\
|\\
\ce{H3C - C  - CH2}\\
|\\
\ce{\underset{2, 2-dihalopropane}{X}}\\
\end{array}\]

\[\begin{array}{cc}
\phantom{.....................}\ce{X}\\
\phantom{.....................}|\\
\ce{H3C - CH2 - CH}\\
\phantom{.....................}|\\
\phantom{.....................}\ce{\underset{1, 1-dihalopropane}{X}}\\
\end{array}\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Haloalkanes and Haloarenes - Intext Question [पृष्ठ १६७]

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एनसीईआरटी Chemistry Part 1 and 2 [English] Class 12
अध्याय 6 Haloalkanes and Haloarenes
Intext Question | Q 6.3 | पृष्ठ १६७

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\[\begin{array}{cc}
\ce{CH3-CH-CH=CH2 + HBr -> A}\\
|\phantom{.....................}\\
\ce{CH3}\phantom{..................}
\end{array}\]

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