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प्रश्न
Write a balanced chemical equation for each of the following reactions :
Action of dilute sulphuric acid on sodium hydroxide.
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उत्तर
NaOH + H2SO4 →NaHSO4 + H2O
NaHSO4 + H2SO4 → Na2SO4 + H2O
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संबंधित प्रश्न
Give reasons for the following:
A piece of wood becomes black when concentrated sulphuric acid is poured on it.
Name the following:
Products obtained by dissolving sulphur dioxide and chlorine in water.
How are the following conversions brought about? Give equation and condition:
Sulphur trioxide to sulphur acid.
Fill in the blank with appropriate word/words :
Oil of Vitriol is ___________
Some properties of sulphuric acid are listed below. Choose the property A, B, C or D which is responsible for the reaction (a) to (e). Some properties may be repeated.
A. Acid
B. Dehydrating agent
C. Non-volatile acid
D. Oxidizing agent
(a) \[\ce{C12H22O11 + nH2SO4 -> 12C + 11H2O + nH2SO4}\]
(b) \[\ce{S + 2H2SO4 -> 3SO2 + 2H2O}\]
(c) \[\ce{NaCl + 2H2SO4 -> NaHSO4 + HCl}\]
(d) \[\ce{CuO + 2H2SO4 -> CuSO4 + H2O}\]
(e) \[\ce{Na2CO3 + H2SO4 -> Na2SO4 + H2O + CO2}\]
Making use only of substances chosen from those given below:
Dilute sulphuric acid
Sodium carbonate
Zinc
Sodium sulphite
Lead
Salcium carbonate
Give the equation for the reaction by which you could obtain:
(i) Hydrogen
(ii) Sulphur dioxide
(iii) Carbon dioxide
(iv) Zinc Carbonate (two steps required).
Write a balanced chemical equation:
When hot and concentrated sulphuric acid reacts with the sulphur.
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation. Each illustrates the above-mentioned properties of sulphuric acid.
The following is the typical property of dilute acid. Complete it by inserting suitable words:
\[\ce{Active metal + Acid -> \underline{\phantom{.......}} + \underline{\phantom{.......}}}\]
What property of Sulphuric acid is exhibited in the following case?
In the preparation of HCI gas when it reacts with Sodium chloride.
