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Without using truth table, show that (p ∨ q) → r ≡ (p → r) ∧ (q → r) - Mathematics and Statistics

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प्रश्न

Without using truth table, show that

(p ∨ q) → r ≡ (p → r) ∧ (q → r)

योग
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उत्तर

L.H.S.

≡ (p ∨ q) → r

≡ ~ (p ∨ q) ∨ r          ....[p → q → ~ p ∨ q]

≡ (~ p ∧ ~ q) ∨ r       ....[De Morgan’s law] 

≡ (~ p ∨ r) ∧ (~ q ∨ r)       .....[Distributive law]

≡ (p → r) ∧ (q → r)             .....[p → q → ~ p ∨ q]

= R.H.S.

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अध्याय 1: Mathematical Logic - Exercise 1.9 [पृष्ठ २२]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 1 Mathematical Logic
Exercise 1.9 | Q 1.5 | पृष्ठ २२

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