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Which of the following functions are strictly decreasing on (0,π2)? A. cos x B. cos 2x C. cos 3x D. tan x - Mathematics

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प्रश्न

Which of the following functions are strictly decreasing on `(0, pi/2)`?

  1. cos x
  2. cos 2x
  3. cos 3x
  4. tan x
योग
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उत्तर

(A) Let (x) = cos x, then   

f' (x) =  - sin x < 0 for all `x in (0, pi/2)`     ....`[∴ sin x > 0 AA x in (0, pi/2)]`

(B) Let f(x) = cos 2x, then

f'(x) = -2 sin 2x < 0 for all `x in (0, pi/2)`    ...(`∵ sin  x > 0 (0, pi) = sin 2x > 0 (0, pi/2)`

= f is strictly decreasing on `(0, pi/2)`

(c) Let f(x) = cos 3x, then f'(x) = -3 sin 3x, 

which assume +ve as well as -ve values in`(0, pi/2)`

`[0 < x < pi/2 = 0 <3x < (3pi)/2]`and `sin 3x > 0 (0, pi/2), sin 3x < o (pi, (3pi)/2)`

∴ f is neither increasing nor decreasing on `(0, pi/2)`

(D) Let f(x) = tan x, then f'(x) = sec2 x > 0 for all `x in (0, pi/2)`        ....`[∵ sec^2 x > 0 AA x in (0, pi/2)]`

= f is strictly increasing on `(0, pi/2)`

Thus, we find that the function in (A) and  (B) are strictly decreasing on `(0, pi/2).`

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अध्याय 6: Application of Derivatives - Exercise 6.2 [पृष्ठ २०६]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 6 Application of Derivatives
Exercise 6.2 | Q 12 | पृष्ठ २०६

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