Advertisements
Advertisements
प्रश्न
Which of the following equations has two real and distinct roots?
विकल्प
x2 – 5x + 6 = 0
x2 – 3x + 6 = 0
x2 – 2x + 5 = 0
x2 – 4x + 6 = 0
Advertisements
उत्तर
x2 – 5x + 6 = 0
Explanation:
Given quadratic equation be
x2 – 5x + 6 = 0
On comparing with ax2 + bx + c = 0;
We have a = 1; b = – 5 and c = 6
Here, discriminant = D
= b2 – 4ac
= (– 5)2 – 4 × 1 × 6
= 25 – 24
= 1 > 0
∴ Roots are real and distinct roots.
APPEARS IN
संबंधित प्रश्न
Solve the equation by using the formula method. 3y2 +7y + 4 = 0
Without solving, examine the nature of roots of the equation 2x2 – 7x + 3 = 0
Find the values of k for the following quadratic equation, so that they have two equal roots.
kx (x - 2) + 6 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
kx2 + 6x + 1 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
x2 - kx + 9 = 0
Prove that both the roots of the equation (x – a)(x – b) + (x – b)(x – c) + (x – c)(x – a) = 0 are real but they are equal only when a = b = c.
Solve the following quadratic equation using formula method only
16x2 - 24x = 1
Solve the following quadratic equation using formula method only
`sqrt 3 "x"^2 + 10 "x" - 8 sqrt 3 = 0`
Find the sum of the roots of the equation x2 – 8x + 2 = 0
Find the roots of the quadratic equation by using the quadratic formula in the following:
–x2 + 7x – 10 = 0
