Advertisements
Advertisements
प्रश्न
Find the nature of the roots of the quadratic equation:
4x2 – 5x – 1 = 0
Advertisements
उत्तर
Given quadratic equation is: 4x2 – 5x – 1 = 0
Comparing the above equation with ax2 + bx + c = 0,
We get a = 4, b = –5 and c = –1
Now, b2 – 4ac = (–5)2 – 4(4)(–1)
= 25 + 16
= 41 > 0
Hence, roots of the quadratic equation are real and distinct.
APPEARS IN
संबंधित प्रश्न
If `x=2/3` and x =−3 are roots of the quadratic equation ax2 + 7x + b = 0, find the values of a and b.
Without solving, examine the nature of roots of the equation 4x2 – 4x + 1 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
kx2 + kx + 1 = -4x2 - x
Determine the nature of the roots of the following quadratic equation :
x2 +3x+1=0
Solve the following quadratic equation using formula method only
`3"x"^2 + 2 sqrt 5x - 5 = 0 `
In each of the following determine the; value of k for which the given value is a solution of the equation:
kx2 + 2x - 3 = 0; x = 2
If (x – a) is one of the factors of the polynomial ax2 + bx + c, then one of the roots of ax2 + bx + c = 0 is:
If (1 – p) is a root of the equation x2 + px + 1 – p = 0, then roots are:
Find whether the following equation have real roots. If real roots exist, find them.
5x2 – 2x – 10 = 0
If x = 3 is one of the roots of the quadratic equation x2 – 2kx – 6 = 0, then the value of k is ______.
