Question

Determine the nature of the roots of the following quadratic equation:

`3x^2-2sqrt6x+2=0`

Answer 1

The given quadric equation is `3x^2-2sqrt6x+2=0`

Here, a = 3, `b=-2sqrt6` and c = 2

As we know that D = b² - 4ac

Putting the value of a = 3, `b=-2sqrt6` and c = 2

`D = (-2sqrt6)^2-4xx3xx2`

= 24 - 24

= 0

Since, D = 0

Therefore, root of the given equation are real and equal.