Advertisements
Advertisements
प्रश्न
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 + 5x + 15 = 0.
Advertisements
उत्तर
x2 + 5x + 15 = 0
Here, aa= 1, b = 5 and c = 15
D = b2 - 4ac
= (5)2 - 4 x 1 x 15
= 25 - 60
= -35
⇒ D < 0
roots are imaginary.
संबंधित प्रश्न
Find the values of k for the following quadratic equation, so that they have two equal roots.
kx (x - 2) + 6 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx + 2 = 0
Find the value(s) of k so that the quadratic equation 3x2 − 2kx + 12 = 0 has equal roots ?
Find the value of the discriminant in the following quadratic equation:
2x2 - 3x + 1 = O
Find the value of the discriminant in the following quadratic equation :
`4 sqrt 3 "x"^2 + 5"x" - 2 sqrt 3 = 0`
If one root of the equation 2x² – px + 4 = 0 is 2, find the other root. Also find the value of p.
Without solving the following quadratic equation, find the value of ‘p’ for which the given equations have real and equal roots: x2 + (p – 3)x + p = 0.
Find the value (s) of k for which each of the following quadratic equation has equal roots : kx2 – 4x – 5 = 0
If α and β are the roots of the equation 2x2 – 3x – 6 = 0. The equation whose roots are `1/α` and `1/β` is:
If b = 0, c < 0, is it true that the roots of x2 + bx + c = 0 are numerically equal and opposite in sign? Justify.
