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प्रश्न
Which of the following triplet pythagorean?
(14, 48, 51)
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उत्तर
The two smallest numbers are 14 and 48. The sum of their squares is:
142 + 482 = 2500, which is not equal to 512 = 2601
Hence, (14, 48, 51) is not a Pythagorean triplet.
संबंधित प्रश्न
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
12 + 22 + 32 + 42 + ... + 102
Find the squares of the following numbers using column method. Verify the result by finding the square using the usual multiplication:
96
Find the squares of the following numbers using diagonal method:
295
Find the square of the following number:
745
Find the square of the following number:
512
There are ______ natural numbers between n2 and (n + 1)2
Write the Pythagorean triplet whose one of the numbers is 4.
Find the area of a square field if its perimeter is 96 m.
Rahul walks 12 m north from his house and turns west to walk 35 m to reach his friend’s house. While returning, he walks diagonally from his friend’s house to reach back to his house. What distance did he walk while returning?
