Advertisements
Advertisements
प्रश्न
Write a Pythagorean triplet whose one member is 6.
Advertisements
उत्तर
The three numbers of the Pythagorean triplet are 2m, m2 - 1 and m2 + 1.
Here, 2m = 6
so, m = 3
Second number (m2 - 1) = (3)2 - 1
= 9 - 1
= 8
Third number (m2 + 1) = (3)2 + 1
= 9 + 1
= 10
Hence the Pythagorean triplet is (6, 8, 10).
APPEARS IN
संबंधित प्रश्न
Find the square of the given number.
93
Find the square of the given number.
46
Write a Pythagorean triplet whose one member is 16.
What will be the units digit of the square of the following number?
4583
Which of the following triplet is pythagorean?
(18, 80, 82)
If one member of a pythagorean triplet is 2m, then the other two members are ______.
The sum of first n odd natural numbers is ______.
For every natural number m, (2m – 1, 2m2 – 2m, 2m2 – 2m + 1) is a pythagorean triplet.
Write the Pythagorean triplet whose one of the numbers is 4.
Find the area of a square field if its perimeter is 96 m.
