Advertisements
Advertisements
प्रश्न
The dimensions of a rectangular field are 80 m and 18 m. Find the length of its diagonal.
Advertisements
उत्तर
Here, length of a rectangular field (l) = 80 m
And breadth of a rectangular field (b) = 18 m
∴ Length of diagonal = `sqrt(l^2 + b^2)`
= `sqrt((80)^2 + (18)^2`
= `sqrt(6400 + 324)`
= `sqrt(6724)`
= 82 m
APPEARS IN
संबंधित प्रश्न
Find the square of the given number.
46
Write a Pythagorean triplet whose one member is 18.
From the pattern, we can say that the sum of the first n positive odd numbers is equal to the square of the n-th positive number. Putting that into formula:
1 + 3 + 5 + 7 + ... n = n2, where the left hand side consists of n terms.
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
12 + 22 + 32 + 42 + ... + 102
Which of the following number square of even number?
373758
Find the square of the following number:
425
The sum of successive odd numbers 1, 3, 5, 7, 9, 11, 13 and 15 is ______.
The sides of a right triangle whose hypotenuse is 17 cm are ______ and ______.
For every natural number m, (2m – 1, 2m2 – 2m, 2m2 – 2m + 1) is a pythagorean triplet.
A 5.5 m long ladder is leaned against a wall. The ladder reaches the wall to a height of 4.4 m. Find the distance between the wall and the foot of the ladder.
