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प्रश्न
Which of the following triplet pythagorean?
(14, 48, 51)
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उत्तर
The two smallest numbers are 14 and 48. The sum of their squares is:
142 + 482 = 2500, which is not equal to 512 = 2601
Hence, (14, 48, 51) is not a Pythagorean triplet.
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संबंधित प्रश्न
What will be the units digit of the square of the following number?
55555
From the pattern, we can say that the sum of the first n positive odd numbers is equal to the square of the n-th positive number. Putting that into formula:
1 + 3 + 5 + 7 + ... n = n2, where the left hand side consists of n terms.
Which of the following triplet is pythagorean?
(18, 80, 82)
Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :
52 + 62 + 72 + 82 + 92 + 102 + 112 + 122
Find the squares of the following numbers using diagonal method:
348
Find a Pythagorean triplet in which one member is 12.
All numbers of a pythagorean triplet are odd.
If x and y are integers such that x2 > y2, then x3 > y3.
Write the Pythagorean triplet whose one of the numbers is 4.
Put three different numbers in the circles so that when you add the numbers at the end of each line you always get a perfect square.

