Advertisements
Advertisements
प्रश्न
When the width of the slit is made double the original width, how would this affect the size and intensity of the central diffraction band?
Advertisements
उत्तर
When the width of slit is made double the original width intensity will get four times of its original value.
Width of central maximum is given by,
`beta = (2Dlambda)/b`
Where, D = Distance between screen and slit,
λ = Wavelength of the light,
b = Size of slit.
So with the increase in size of slit the width of central maxima decreases. Hence, double the size of the slit would result in half the width of the central maxima.
APPEARS IN
संबंधित प्रश्न
On the basis of Huygens' wave theory of light prove that velocity of light in a rarer medium is greater than velocity of light in a denser medium.
Use Huygens' principle to verify the laws of refraction.
The refractive indices of water and diamond are `4/3` and 2.42 respectively. Find the speed of light in water and diamond. (c = 3x108 m/s)
Use Huygens’s principle to explain the formation of diffraction pattern due to a single slit illuminated by a monochromatic source of light.
Answer the following question.
Define the term wavefront. Using Huygen's wave theory, verify the law of reflection.
According to Huygens principle, ______.
According to Huygen's construction, relation between old and new wavefront is ______.
Answer the following question briefly and to the point:
What is the phase difference between any two points lying on the same wavefront?
Huygen's conception of secondary waves ______.
Represent diagrammatically how the incident planar wavefronts of wavelength λ pass through an aperture of size d, when d is approximately equal to λ.
