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When a Photon Stimulates the Emission of Another Photon, the Two Photons Have

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प्रश्न

When a photon stimulates the emission of another photon, the two photons have
(a) same energy
(b) same direction
(c) same phase
(d) same wavelength

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उत्तर

(a) same energy
(b) same direction
(c) same phase
(d) same wavelength

When a photon stimulates the emission of another photon, the two photons have same energy, direction, phase, and wavelength or we can say that the two photons are coherent.
When an atom is present in its excited state then if a photon of energy equal to the energy gap between the excited state and any lower stable state is incident on this atom then the atom transits from upper state to the lower stable state by emitting a photon of energy equal to the energy gap between the two states. It is called stimulated emission. The emitted photon and incident photon have same energy and hence same wavelength. Also these two photons will be in phase and in the same direction. This process of producing monochromatic  and unidirectional light is called lasing action.

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अध्याय 43: Bohr’s Model and Physics of Atom - MCQ [पृष्ठ ३८४]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 43 Bohr’s Model and Physics of Atom
MCQ | Q 6 | पृष्ठ ३८४

संबंधित प्रश्न

Explain, giving reasons, which of the following sets of quantum numbers are not possible.

  1. n = 0, l = 0, ml = 0, ms = + ½
  2. n = 1, l = 0, ml = 0, ms = – ½
  3. n = 1, l = 1, ml = 0, ms = + ½
  4. n = 2, l = 1, ml = 0, ms = – ½
  5. n = 3, l = 3, ml = –3, ms = + ½
  6. n = 3, l = 1, ml = 0, ms = + ½

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Statements I: According to Bohr's model of an atom, qualitatively the magnitude of velocity of electron increases with decrease in positive charges on the nucleus as there is no strong hold on the electron by the nucleus.

Statement II: According to Bohr's model of an atom, qualitatively the magnitude of velocity of electron increase with a decrease in principal quantum number.
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