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What would be the electron dot structure of carbon dioxide which has the formula CO2?

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What would be the electron dot structure of carbon dioxide which has the formula CO2?

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अध्याय 4: Carbon and its Compounds - Intext Questions [पृष्ठ ६१]

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एनसीईआरटी Science [English] Class 10
अध्याय 4 Carbon and its Compounds
Intext Questions | Q 1. | पृष्ठ ६१

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

What would be the electron dot structure of a molecule of sulphur which is made up of eight atoms of sulphur? (Hint – the eight atoms of sulphur are joined together in the form of a ring.)


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State whether the following statement is true or false:

Diamond and graphite are the covalent compounds of carbon element (C)


What do you call the compounds having the same molecular formula but different structural arrangements of atoms?


What type of bonds are present in H molecule? Draw their electron-dot structures.


Fill in the following blank with suitable word:

The form of carbon which is known as black lead is ...........


Draw the electron-dot structure of  HCl  compound and state the type of bonding.


A covalent molecule having a double bond between its atoms is:
(a) Hydrogen
(b) Oxygen
(c) water
(d) ammonia


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(a) lithium
(b) charcoal
(c) lead
(d) graphite


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(a) 2
(b) 5
(c) 3
(d) 4


Give the characteristic properties of covalent compounds.


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Choose and write the correct option.

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Explain the following briefly:
Cl2 is a non polar molecule, while HCl is a polar molecule.


Explain why carbon tetrachloride does not dissolve in water.


Draw the electron dot structure of covalent compound methane (non polar) and HCL (polar) and give two difference between them.


What is the difference between a polar covalent compound and a non-polar covalent compound?


Complete the following activity.

Write the names of the hydrocarbons for the following structural formula.

(isobutylene, cyclohexane, propene, cyclohexene, cyclopentane, benzene, propyne, isobutane, propane)

\[\begin{array}{cc}\phantom{......}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{..}\\
\phantom{.....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C = C}\\\phantom{.....}|\phantom{.........}|\\
\phantom{.....}\ce{H}\phantom{........}\ce{H}\end{array}\]
 

Consider the coordination compound, K2[Cu(CN)4]. A coordinate covalent bond exists between:


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