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प्रश्न
What happens when ethylene is passed through cold dilute alkaline potassium permanganate.
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उत्तर
\[\ce{\underset{\text{Ethylene}}{CH2 = CH} + H2O + (O) ->[cold dil. alkaline KMnO4] \underset{\text{Ethylene glycol}}{CH2OH - CH2OH}}\]
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\[\begin{array}{cc}
\phantom{..............................}\ce{CH3}\\
\phantom{............................}|\\
\ce{CH3 - C = CH2 + HBr ->[benzoyl][peroxide] CH3 - CH - CH2Br}\\
|\phantom{....................................}\\
\ce{CH_3}\phantom{.................................}
\end{array}\]
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