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प्रश्न
What happens when ethylene is passed through cold dilute alkaline potassium permanganate.
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उत्तर
\[\ce{\underset{\text{Ethylene}}{CH2 = CH} + H2O + (O) ->[cold dil. alkaline KMnO4] \underset{\text{Ethylene glycol}}{CH2OH - CH2OH}}\]
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\ce{CH2 - CH2 ->[Zn/C2H5OH]}\\
|\phantom{.......}|\phantom{..............}\\
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\phantom{...............................}\ce{CH3}\\
\phantom{............................}|\\
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|\phantom{....................................}\\
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