Advertisements
Advertisements
प्रश्न
Verify the following:
`((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
Advertisements
उत्तर
Taking L.H.S. = `((3p)/7 + 7/(6p))^2 - (3/7p + 7/(6p))^2 = 2`
= `[((3p)/7 + 7/(6p)) + ((3p)/7 - 7/(6p))][((3p)/7 + 7/(6p)) - ((3p)/7 - 7/(p))]` ...[Using the identity, a2 – b2 = (a + b)(a – b)]
= `((3p)/7 + 7/(6p) + (3p)/7 - 7/(6p))((3p)/7 + 7/(6p) - (3p)/7 + 7/(6p))`
= `(6p)/7 xx 14/(6p)`
= 2
= R.H.S.
Hence verified.
APPEARS IN
संबंधित प्रश्न
Expand: (3x + 4y)(3x - 4y)
Factorise the following expressions
m2 + m – 72
Factorise the following algebraic expression by using the identity a2 – b2 = (a + b)(a – b)
25a2 – 49b2
If X = a2 – 1 and Y = 1 – b2, then find X + Y and factorize the same
Find the value of (x – y)(x + y)(x2 + y2)
Multiply the following:
(a2 – b2), (a2 + b2)
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
p5 – 16p
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
16x4 – 81
Factorise the expression and divide them as directed:
(x3 + x2 – 132x) ÷ x(x – 11)
