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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

U-shaped Wire is Dipped in a Soap Solution and Removed. the Thin Soap Film Formed Between the Wire and the Light Slider Supports a Weight of 1.5 × 10–2 N (Which Includes the Small Weight of the Slider). the Length of the Slider is 30 Cm. What is the Surface Tension of the Film

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प्रश्न

A U-shaped wire is dipped in a soap solution and removed. The thin soap film formed between the wire and the light slider supports a weight of 1.5 × 10–2 N (which includes the small weight of the slider). The length of the slider is 30 cm. What is the surface tension of the film?

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उत्तर १

The weight that the soap film supports, W = 1.5 × 10–2 N

Length of the slider, l = 30 cm = 0.3 m

A soap film has two free surfaces.

∴Total length = 2l = 2 × 0.3 = 0.6 m

Surface tension, `S = "Force of Weight"/"2l"`

`= (1.5 xx 10^(-2))/0.6 = 2.5 xx 10^(-2) "N/m"`

Therefore, the surface tension of the film is 2.5 × 10–2 N m–1.

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उत्तर २

 In present case force of surface tension is balancing the weight of 1.5 x 10-2 N, hence force of surface tension, F = 1.5 x 10-2 N.

Total length of liquid film, l = 2 x 30 cm = 60 cm = 0.6 m because the liquid film has two surfaces.

Surface tension, T = F/l =1.5 x 10-2 N/0.6m =2.5 x 10-2 Nm-1

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अध्याय 9: Mechanical Properties of Fluids - Exercises [पृष्ठ २६९]

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एनसीईआरटी Physics Part 1 and 2 [English] Class 11
अध्याय 9 Mechanical Properties of Fluids
Exercises | Q 17 | पृष्ठ २६९

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