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प्रश्न
Two pea plants - one with round yellow seeds (RRYY) and another with wrinkled green (rryy) seeds produce F1 progeny that have round, yellow (RrYy) seeds.
When F1 plants are self-pollinated, which new combination of characters is expected in F2 progeny? How many seeds with these new combinations of characters will be produced when a total 160 seeds are produced in F2 generation? Explain with reason.
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उत्तर
Round green : 30
Wrinkled yellow : 30
New combinations are produced because of the independent inheritance of seed shape and seed colour trait.
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संबंधित प्रश्न
A homozygous Tall plant (T) bearing red coloured (R) flowers is crossed with a homozygous dwarf plant (t) bearing white flowers (r):
(1) Give the Genotype and Phenotype of the F2 generation.
(2) Give the possible combinations of the gametes that can be obtained from the F2 hybrid.
(3) Give the dihybrid ratio and the phenotype of the offsprings of the F2 generation when two plants of the F1 generation above are crossed.
Complete the following sentence with appropriate word:
_______ is the ratio of dihybrid cross.
Multiple Choice Question
When two individuals differing in at least one character are crossed, the process is known as:
The physical expression of a gene is called ______.
A cross between two tall plants resulted in offspring having few dwarf plants. What would be the genotypes of both the parents?
Two linked genes a and b show 20% recombination. The individuals of a dihybrid cross between ++ /++ × ab/ab shall show gametes ______.
Mendel’s last law is ______.
The process of mating between closely related individuals is ______.
A fruit fly exhibiting both male and female traits is ______.
Which one of the following genetic ratios will be obtained in a dihybrid test cross:
