Advertisements
Advertisements
प्रश्न
Two long straight parallel conductors carrying steady currents I1 and I2 are separated by a distance 'd'. Explain briefly, with the help of a suitable diagram, how the magnetic field due to one conductor acts on the other. Hence deduce the expression for the force acting between the two conductors. Mention the nature of this force.
Advertisements
उत्तर
Assumption: Current flows in the same direction.
Using Right hand thumb rule, the direction of the magnetic field at point P due to current I2 is perpendicular to the plane of paper and inwards.
Similarly, at point Q on X2Y2, the direction of magnetic field due to current I1 is perpendicularly outward.
Using Fleming’s left hand rule we can find the direction of forces F12 and F21 which are in opposite directions thus,
By Ampere’s circuited law, we have,
`B^2 =mu_0/(4pi) (2I_2)/d`
Now, F12 = I1LB2 (Where L ≡ length of the conductors)
`F_12 =(mu_0)/(4pi) (2I_1I_2L)/d =mu_0/(2pi)(I_1I_2L)/d`
In similar manner we get,
`F_21 =mu_0/(2pi) (I_1I_2L)/d .... (1)`
From above we get the magnitude of forces F12 and F21 are equal but in opposite direction. So,
F12 = −F21
Therefore, two parallel straight conductors carrying current in the same direction attract each other.
Similarly, we can prove if two parallel straight conductors carry currents in opposite direction, they repel each other with the same magnitude as equation (1).
संबंधित प्रश्न
Two proton beams going in the same direction repel each other whereas two wires carrying currents in the same direction attract each other. Explain.
Consider a long, straight wire of cross-sectional area A carrying a current i. Let there be n free electrons per unit volume. An observer places himself on a trolley moving in the direction opposite to the current with a speed \[v = \frac{i}{\text{nAe}}\] and separation from the wire by a distance r. The magnetic field seen by the observer is very nearly
Consider the situation shown in figure. The wire PQ has mass m, resistance r and can slide on the smooth, horizontal parallel rails separated by a distance l. The resistance of the rails is negligible. A uniform magnetic field B exists in the rectangular region and a resistance R connects the rails outside the field region. At t = 0, the wire PQ is pushed towards right with a speed v0. Find (a) the current in the loop at an instant when the speed of the wire PQ is v, (b) the acceleration of the wire at this instant, (c) the velocity vas a functions of x and (d) the maximum distance the wire will move.
A magnetic field that varies in magnitude from point to point but has a constant direction (east to west) is set up in a chamber. A charged particle enters the chamber and travels undeflected along a straight path with constant speed. What can you say about the initial velocity of the particle?
-
The presence of a large magnetic flux through a coil maintains a current in the coil if the circuit is continuous.
-
A coil of a metal wire kept stationary in a non– uniform magnetic field has an e.m.f induced in it.
-
A charged particle enters a region of uniform magnetic field at an angle of 85° to the magnetic lines of force, the path of the particle is a circle.
-
There is no change in the energy of a charged particle moving in a magnetic field although a magnetic force is acting on it.
If an electron is moving with velocity `vecnu` produces a magnetic field `vec"B"`, then ______.
A moving charge will gain kinetic energy due to the application of ______.
A charged particle moving in a magnetic field experiences a resultant force ______
A beam of protons with speed 4 × 105 ms-1 enters a uniform magnetic field of 0.3 T at an angle of 60° to the magnetic field. The pitch of the resulting helical path of protons is close to :
(Mass of the proton = 1.67 × 10-27 kg, charge of the proton = 1.69 × 10-19 C)
A wire carrying current i has the configuration shown in figure. For the magnetic field to be zero at the centre of the circle, θ must be:
