Advertisements
Advertisements
प्रश्न
Three 250 W heaters are connected in parallel to a 100 V supply, Calculate total current taken from the supply.
Advertisements
उत्तर

Total current drawn from the supply
I = I1 + I2 + I3
Since each heater is of 250 W.
Therefore, I1 = I2 = I3
and total current I = 3I,
or I = `3 (250/100)` = 3 (2.5 A) = 7.5 A
संबंधित प्रश्न
What is the maximum power in kilowatts of the appliance that can be connected safely to a 13 A ; 230 V mains socket?
1Kwh =`( 1 "volt "xx 1 am pere xx.............)/1000`
An electric bulb is rated 250 W, 230 V. Calculate:
- the energy consumed in one hour
- the time in which the bulb will consume 1.0 kWh energy when connected to 230 V mains.
An immersion heater rated 1000 W, 220 V is used to heat 0.01 m3 of water. Assuming that the power is supplied at 220 V and 60% of the power supplied is used to heat the water, how long will it take to increase the temperature of the water from 15°C to 40°C?
Express watt hour and kilowatt hour in joule.
Why is the heating element of an electric oven wound on a helix? State the reason.
Three 250 W heaters are connected in parallel to a 100 V supply, Calculate the energy supply in kWh to the three heaters in 5 hour.
Find the energy released by a current of 0.25 amperes flowing through a heater for 5 minutes. The p.d. is 230 V.
An electric bulb is rated as 100W – 250V. What information does it convey? Calculate the current through the filament of the bulb.
Unit of electric power may also be expressed as:
