Advertisements
Advertisements
प्रश्न
Three 250 W heaters are connected in parallel to a 100 V supply, Calculate total current taken from the supply.
Advertisements
उत्तर
Total current drawn from the supply
I = I1 + I2 + I3
Since each heater is of 250 W.
Therefore, I1 = I2 = I3
and total current I = 3I,
or I = `3 (250/100)` = 3 (2.5 A) = 7.5 A
संबंधित प्रश्न
What is the SI unit of (i) electric energy, and (ii) electric power?
Calculate the cost of operating a heater of 500 W for 20 hours at the rate of Rs 3.90 per unit.
The commercial unit of energy is :
(a) watt
(b) watt-hour
(c) kilowatt-hour
(d) kilo-joule
Electrical power p is given by the expression P = (Q × V) ÷ time. Express the power P in terms of current and resistance explaining the meaning of symbols used there in.
The diagram below shows a magnetic kept just below the conductor AB which is kept in North South direction.
(i) In which direction will the needle deflect when the key is closed ?
(ii) Why is the deflection produced ?
(iii) What will be the change in the deflection if the magnetic needle is taken just above the conductor AB ?
(iv) Name one device which works on this principle.
An electric iron rated 750 W is operated for 2 hours/day. How much energy is consumed by the electric iron for 30 days?
Name three main characteristics of an heating element.
Which material is the calorimeter commonly made of? Give one reason for using this material.
The equation I2R seems to suggest that the rate of heating in a resistor is reduced if resistance decreases, whereas equation P = V2/R suggests just the opposite. How do you reconcile this problem?
1 kWh = ____________
