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There is a working women's hostel in a town, where 75% are from neighbouring town. The rest all are from the same town. 48% of women who hail from the same town are graduates and 83% of the women who - Mathematics and Statistics

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प्रश्न

There is a working women's hostel in a town, where 75% are from neighbouring town. The rest all are from the same town. 48% of women who hail from the same town are graduates and 83% of the women who have come from the neighboring town are also graduates. Find the probability that a woman selected at random is a graduate from the same town

योग
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उत्तर

Let the total number of women be 100.

∴ n(S) = 100

Let event N: Women are from neighbouring town,

event W: Women are from same town and

event G: Women are graduates.

Number of women from neighbouring town,
n(N) = 75

Number of women from same town,
n(W) = 25

∴ P(N) = `("n"("N"))/("n"("S")) = 75/100` and

P(W) = `("n"("W"))/("n"("S")) = 25/100` 

`"P"("G"//"N"), "P"("G"//"W")` represent probabilities that woman is graduate given that she is from neighbouring town or same town respectively.

∴ `"P"("G"//"N") = ("n"("G"//"N"))/("n"("S")) = 83/100` and

`"P"("G"//"W") = ("n"("G"//"W"))/("n"("S")) = 48/100`

By Bayes’ theorem, the probability that a women selected at random is a graduate from the same town, is given by

`"P"("W"//"G") = ("P"("W") * "P"("G"//"W"))/("P"("W")*"P"("G"//"W") + "P"("N")*"P"("G"//"N"))``

= `((25/100)*(48/100))/((25/100)*(48/100) + (75/100)*(83/100))`

= `(25 xx 48)/((25 xx 48) + (75 xx 83))`

= `48/(48 + 249)`

= `16/99`

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अध्याय 9: Probability - Exercise 9.4 [पृष्ठ २०९]

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