Advertisements
Advertisements
प्रश्न
The supply S for a commodity at price P is given by S = P2 + 9P − 2. Find the marginal supply when price is 7/-.
Advertisements
उत्तर
Given, S = P2 + 9P – 2
Marginal supply = `("dS")/("dP")`
= `"d"/("dP")("P"^2 + 9"P" -2)`
= `"d"/("dP")("P"^2) + 9"d"/("dP")("P") - "d"/("dP")(2)`
= 2P + 9(1) – 0
= 2P + 9
When P = 7,
Marginal supply =`(("dS")/("dP"))_("P" = 7)`
= 2(7) + 9
= 14 + 9
= 23
∴ Marginal supply is 23, at P = 7.
APPEARS IN
संबंधित प्रश्न
Find the derivative of the following w. r. t.x. : `(3e^x-2)/(3e^x+2)`
Find the derivative of the following w. r. t. x. : `(xe^x)/(x+e^x)`
Find the derivative of the following function by the first principle: 3x2 + 4
Find the derivative of the following function by the first principle: `x sqrtx`
Differentiate the following function w.r.t.x : `(x^2 + 1)/x`
Differentiate the following function w.r.t.x. : `1/("e"^x + 1)`
Differentiate the following function w.r.t.x. : `x/log x`
Differentiate the following function w.r.t.x. : `2^x/logx`
Differentiate the following function w.r.t.x. : `((2"e"^x - 1))/((2"e"^x + 1))`
Solve the following example: If for a commodity; the demand function is given by, D = `sqrt(75 − 3"P")`. Find the marginal demand function when P = 5.
Differentiate the following function w.r.t.x. : `xsqrt x`
Differentiate the followingfunctions.w.r.t.x.: `1/sqrtx`
Find `dy/dx` if y = x2 + 2x – 1
Find `dy/dx if y = ((logx+1))/x`
Find `dy/dx if y = "e"^x/logx`
The relation between price (P) and demand (D) of a cup of Tea is given by D = `12/"P"`. Find the rate at which the demand changes when the price is Rs. 2/-. Interpret the result.
Differentiate the following w.r.t.x :
y = `3 cotx - 5"e"^x + 3logx - 4/(x^(3/4))`
