Advertisements
Advertisements
प्रश्न
The supply S for a commodity at price P is given by S = P2 + 9P − 2. Find the marginal supply when price is 7/-.
Advertisements
उत्तर
Given, S = P2 + 9P – 2
Marginal supply = `("dS")/("dP")`
= `"d"/("dP")("P"^2 + 9"P" -2)`
= `"d"/("dP")("P"^2) + 9"d"/("dP")("P") - "d"/("dP")(2)`
= 2P + 9(1) – 0
= 2P + 9
When P = 7,
Marginal supply =`(("dS")/("dP"))_("P" = 7)`
= 2(7) + 9
= 14 + 9
= 23
∴ Marginal supply is 23, at P = 7.
APPEARS IN
संबंधित प्रश्न
Find the derivative of the following w. r. t. x. : `(xe^x)/(x+e^x)`
Find the derivative of the following function by the first principle: 3x2 + 4
Differentiate the following function w.r.t.x : `(x^2 + 1)/x`
Solve the following example: The total cost of ‘t’ toy cars is given by C=5(2t)+17. Find the marginal cost and average cost at t = 3.
Solve the following example: The demand function is given as P = 175 + 9D + 25D2 . Find the revenue, average revenue, and marginal revenue when demand is 10.
Differentiate the following function .w.r.t.x. : x5
Differentiate the following function w.r.t.x. : `xsqrt x`
Find `dy/dx if y=(sqrtx+1)^2`
Find `dy/dx if y = (sqrtx + 1/sqrtx)^2`
Find `dy/dx` if y = (1 – x) (2 – x)
Find `dy/dx if y=(1+x)/(2+x)`
Find `dy/dx if y = ((logx+1))/x`
The relation between price (P) and demand (D) of a cup of Tea is given by D = `12/"P"`. Find the rate at which the demand changes when the price is Rs. 2/-. Interpret the result.
Differentiate the following w.r.t.x :
y = `sqrt(x) + tan x - x^3`
Differentiate the following w.r.t.x :
y = `log x - "cosec" x + 5^x - 3/(x^(3/2))`
Differentiate the following w.r.t.x :
y = `3 cotx - 5"e"^x + 3logx - 4/(x^(3/4))`
