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Find the derivative of the following w. r. t.x. : 3ex-23ex+2 - Mathematics and Statistics

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प्रश्न

Find the derivative of the following w. r. t.x. : `(3e^x-2)/(3e^x+2)`

योग
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उत्तर

Let y = `(3"e"^x - 2)/(3"e"^x + 2)`

Differentiating w.r.t. x, we get

`dy/dx = d/dx((3"e"^x - 2)/(3"e"^x + 2))`

=`((3"e"^x + 2) d/dx(3"e"^x - 2) - (3"e"^x - 2) d/dx(3"e"^x + 2))/((3"e"^x + 2)^2)`

= `((3"e"^x + 2)(d/dx(3"e"^x) - d/dx(2)) - (3"e"^x - 2)(d/dx(3"e"^x) + d/dx(2)))/((3"e"^x + 2)^2)`

= `((3"e"^x + 2)(3"e"^x - 0) - (3"e"^x - 2)(3"e"^x + 0))/((3"e"^x + 2)^2)`

= `(3"e"^x(3"e"^x + 2) - 3"e"^x(3"e"^x - 2))/((3"e"^x + 2)^2)`

= `(3"e"^x(3"e"^x + 2 - 3"e"^x + 2))/(3"e"^x + 2)^2`

= `(3"e"^x(4))/(3"e"^x + 2)^2`

= `(12"e"^x)/(3"e"^x + 2)^2`

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Rules of Differentiation (Without Proof)
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Differentiation - Exercise 9.1 [पृष्ठ १२०]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 11 Maharashtra State Board
अध्याय 9 Differentiation
Exercise 9.1 | Q IV. (4) | पृष्ठ १२०

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