हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

The Stress-strain Graphs for Materials a and B Are Shown in Figure Which of the Materials Has the Greater Young’S Modulus and Which of the Two is the Stronger Material?

Advertisements
Advertisements

प्रश्न

The stress-strain graphs for materials A and B are shown in Figure

The graphs are drawn to the same scale.

(a) Which of the materials has the greater Young’s modulus?

(b) Which of the two is the stronger material?

Advertisements

उत्तर १

a) For a given strain, the stress for material A is more than it is for material B, as shown in the two graphs

Young’s modulus  = Stress/Strain

For a given strain, if the stress for a material is more, then Young’s modulus is also greater for that material. Therefore, Young’s modulus for material A is greater than it is for material B.

b) The amount of stress required for fracturing a material, corresponding to its fracture point, gives the strength of that material. Fracture point is the extreme point in a stress-strain curve. It can be observed that material A can withstand more strain than material B. Hence, material A is stronger than material B.

 

shaalaa.com

उत्तर २

a) From the two graphs we note that for a given strain, stress for A is more than that of B. Hence Young’s modulus =(Stress /Strain) is greater for A than that of B.

b) The strength of a material is determined by the amount of stress required to cause the fracture. This stress corresponds to the point of fracture. The stress corresponding to the point of fracture in A is more than for B. So, material A is stronger than material B.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Mechanical Properties of Solids - Exercises [पृष्ठ २४३]

APPEARS IN

एनसीईआरटी Physics Part 1 and 2 [English] Class 11
अध्याय 8 Mechanical Properties of Solids
Exercises | Q 3 | पृष्ठ २४३

संबंधित प्रश्न

The figure shows the strain-stress curve for a given material. What are (a) Young’s modulus and (b) approximate yield strength for this material?


Two wires of diameter 0.25 cm, one made of steel and the other made of brass are loaded as shown in Fig. 9.13. The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m. Compute the elongations of the steel and the brass wires.


Consider the situation shown in figure. The force F is equal to the m2 g/2. If the area of cross section of the string is A and its Young modulus Y, find the strain developed in it. The string is light and there is no friction anywhere.


A uniform rectangular block of mass of 50 kg is hung horizontally with the help of three wires A, B and C each of length and area of 2m and 10mm2 respectively as shown in the figure. The central wire is passing through the centre of gravity and is made of material of Young's modulus 7.5 x 1010 Nm−2 and the other two wires A and C symmetrically placed on either side of the wire B are of Young's modulus 1011 Nm2  The tension in the wires A and B will be in the ratio of: 


The temperature of a wire is doubled. The Young’s modulus of elasticity ______.


The Young’s modulus for steel is much more than that for rubber. For the same longitudinal strain, which one will have greater tensile stress?


What is the Young’s modulus for a perfect rigid body ?


A steel rod (Y = 2.0 × 1011 Nm–2; and α = 10–50 C–1) of length 1 m and area of cross-section 1 cm2 is heated from 0°C to 200°C, without being allowed to extend or bend. What is the tension produced in the rod?


A truck is pulling a car out of a ditch by means of a steel cable that is 9.1 m long and has a radius of 5 mm. When the car just begins to move, the tension in the cable is 800 N. How much has the cable stretched? (Young’s modulus for steel is 2 × 1011 Nm–2.)


A steel wire of mass µ per unit length with a circular cross section has a radius of 0.1 cm. The wire is of length 10 m when measured lying horizontal, and hangs from a hook on the wall. A mass of 25 kg is hung from the free end of the wire. Assuming the wire to be uniform and lateral strains << longitudinal strains, find the extension in the length of the wire. The density of steel is 7860 kg m–3 (Young’s modules Y = 2 × 1011 Nm–2).


A steel rod of length 2l, cross sectional area A and mass M is set rotating in a horizontal plane about an axis passing through the centre. If Y is the Young’s modulus for steel, find the extension in the length of the rod. (Assume the rod is uniform.)


A metal wire of length L, area of cross section A and Young's modulus Y behaves as a spring of spring constant k given by:


If the length of a wire is made double and the radius is halved of its respective values. Then, Young's modules of the material of the wire will ______.


What does the dimensional formula [L⁻¹M¹T⁻²] represent?


Which of the following statements about Young's modulus is correct?


In the formula Y = MgL/(πr²l), what does 'l' represent?


The maximum elongation of a steel wire of 1 m length if the elastic limit of steel and its Young’s modulus, respectively, are 8 × 108 Nm−2 and 2 × 1011 Nm2, is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×