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The Length of a Metal Wire Is L1 When the Tension in It T1 and Is L2 When the Tension Is T2. the Natural Length of the Wire is - Physics

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प्रश्न

The length of a metal wire is l1 when the tension in it T1 and is l2 when the tension is T2. The natural length of the wire is

विकल्प

  • \[\frac{\text{ l}_1 + \text{l}_2}{2}\]

  • \[\sqrt{\text{ l}_1 \text{l}_2}\]

  • \[\frac{\text{l}_1 \text{T}_2 - \text{l}_2 \text{T}_1}{\text{T}_2 - \text{T}_1}\]

  • \[\frac{\text{l}_1 \text{T}_2 + \text{l}_2 \text{T}_1}{\text{T}_2 + \text{T}_1}\]

MCQ
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उत्तर

\[\text{ Let the Young's modulus be Y }. \]

\[\text{C . S . A . = A}\]

\[\text{Actual length of the wire = L}\]

\[\text{For tension T}_1 : \]

\[Y = \frac{\frac{T_1}{A}}{\frac{\left( \text{L - l}_1 \right)}{L}} . . . (1)\]

\[\text{ For tension T}_2 : \]

\[Y = \frac{\frac{T_2}{A}}{\frac{\left( \text{L - l}_2 \right)}{L}} . . . (2)\]

\[\text{ From (1) and (2): }\]

\[\frac{\frac{T_1}{A}}{\frac{\left( L - l_1 \right)}{L}} = \frac{\frac{T_2}{A}}{\frac{\left( L - l_2 \right)}{L}}\]

\[ \Rightarrow \frac{T_1}{\left( L - l_1 \right)} = \frac{T_2}{\left( L - l_2 \right)}\]

\[ \Rightarrow L = \frac{T_2 l_1 - T_1 l_2}{T_2 - T_1}\]

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अध्याय 14: Some Mechanical Properties of Matter - MCQ [पृष्ठ २९८]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 14 Some Mechanical Properties of Matter
MCQ | Q 8 | पृष्ठ २९८

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