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प्रश्न
The number `sqrt2` is shown on a number line. Steps are given to show `sqrt3` on the number line using `sqrt2`. Fill in the boxes properly and complete the activity.
Activity :
- The point Q on the number line shows the number ______.
- A line perpendicular to the number line is drawn through the point Q. Point R is at unit distance from Q on the line.
- Right angled ∆ORQ is obtained by drawing seg OR.
`l ("OQ") = sqrt2` , `l("QR") = 1`
`therefore` by Pythagoras theorem,
`[l("OR")]^2 = [l("OQ")]^2 + [l("QR")]^2 `
= `square^2`+ `square^2` = `square` + `square`
= `square`
∴ l(OR) = `square`
Draw an arc with centre O and radius OR. Mark the point of intersection of the line and the arc as C. The point C shows the number `sqrt3`.
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उत्तर

- The point Q on the number line shows the number `bb\underlinesqrt2`.
- A line perpendicular to the number line is drawn through the point Q. Point R is at unit distance from Q on the line.
- Right angled ∆ ORQ is obtained by drawing seg OR.
- l(OQ) = `sqrt2` , l(QR) = 1
∴ by pythagoras theorem,
[l(OR)]2 = [l(OQ)]2 + [l(QR)]2
= `bbsqrt2^2 + bb1^2 = bb2 + bb1`
= 3
∴ l(OR) = `bbsqrt2`
Draw an arc with centre O and radius OR. Mark the point of intersection of the line and the arc as C. The point C shows the number line `sqrt3`.
संबंधित प्रश्न
Write five rational numbers which are smaller than 2.
Show the following numbers on a number line. Draw a separate number line for each example.
(1)`3/2 , 5/2 , -3/2`
(2)`7/5 , (-2)/5 , (-4)/5`
(3) `(-5)/8 , 11/8`
(4)`13/10 , (-17)/10`
Show the following numbers on a number line. Draw a separate number line for the example.
`(-5)/8 , 11/8`
Show the number √5 on the number line.
Show the number √7 on the number line.
Find the rational numbers represented by the question marks marked on the following number line
The rational numbers can be represented on the number line.
Write the following rational numbers in the descending order.
`8/7, (-9)/8, (-3)/2, 0, 2/5`
Find a rational number exactly halfway between:
`1/6` and `1/9`
Find a rational number exactly halfway between:
`5/(-13)` and `(-7)/9`
