Advertisements
Advertisements
प्रश्न
Write the following rational numbers in the descending order.
`8/7, (-9)/8, (-3)/2, 0, 2/5`
Advertisements
उत्तर
Given numbers are `8/7, (-9)/8, (-3)/2, 0, 2/5`
First, we convert the given numbers as like denominators.
LCM of 7, 8, 2, 5 = 2 × 7 × 4 × 5 = 280
Now, `8/7 = 8/7 xx 40/40 = 320/280`
`(-9)/8 = (-9)/8 xx 35/35 = (-315)/280`
`(-3)/2 = (-3)/2 xx 140/140 = (-420)/280`
`2/5 = 2/5 xx 56/56 = 112/280`
In descending order,
∵ `320/280 > 112/280 > 0 > (-315)/280 > (-420)/280`
⇒ `8/7 > 2/5 > 0 > (-9)/8 > (-3)/2`
APPEARS IN
संबंधित प्रश्न
Observe the number line and answer the questions.
- Which number is indicated by point B?
- Which point indicates the number `1 3/4`?
- State whether the statement ‘the point D denotes the number `5/2`’ is true or false.
Show the following numbers on a number line. Draw a separate number line for the example.
`13/10 , (-17)/10`
The number `sqrt2` is shown on a number line. Steps are given to show `sqrt3` on the number line using `sqrt2`. Fill in the boxes properly and complete the activity.
Activity :
- The point Q on the number line shows the number ______.
- A line perpendicular to the number line is drawn through the point Q. Point R is at unit distance from Q on the line.
- Right angled ∆ORQ is obtained by drawing seg OR.
`l ("OQ") = sqrt2` , `l("QR") = 1`
`therefore` by Pythagoras theorem,
`[l("OR")]^2 = [l("OQ")]^2 + [l("QR")]^2 `
= `square^2`+ `square^2` = `square` + `square`
= `square`
∴ l(OR) = `square`
Draw an arc with centre O and radius OR. Mark the point of intersection of the line and the arc as C. The point C shows the number `sqrt3`.
Show the number √7 on the number line.
Evaluate:
`2 + (-3)/5`
Find the rational numbers represented by the question marks marked on the following number line
Find the rational numbers represented by the question marks marked on the following number line
Draw a number line and represent the following rational numbers on it
`(-8)/3`
On a number line, `(-1)/2` is to the ______ of zero (0).
Find a rational number exactly halfway between:
`1/6` and `1/9`
