Advertisements
Advertisements
प्रश्न
The given figure shows a rhombus ABCD in which angle BCD = 80°. Find angles x and y.
Advertisements
उत्तर
In rhombus ABCD, diagonals AC and BD bisect each other at 90°
∠BCD = 80°
Diagonals bisect the opposite angles also ∠BCD =
∠BAD (Opposite angles of rhombus)
∠BAD = 80° and ∠ABC = ∠ADC = 180° – 80° = 100°
Diagonals bisect opposite angles
∠OCB or ∠PCB =`80^circ/2` = 40°
In ∆PCM,
Ext. CPD = ∠OCB + ∠PMC
110° = 40° + x
⇒ x = 110° – 40° = 70°
and ∠ADO = `1/2` ∠ADC = `1/2 xx 100^circ = 50^circ`
Hence x = 70° and y = 50°
APPEARS IN
संबंधित प्रश्न
In the following figure RISK and CLUE are parallelograms. Find the measure of x.
The measure of one angle of a parallelogram is 70°. What are the measures of the remaining angles?
In a parallelogram ABCD, ∠D = 135°, determine the measure of ∠A and ∠B.
ABCD is a parallelogram in which ∠A = 70°. Compute ∠B, ∠C and ∠D.
Fill in the blank, in the following, so as to make the statement true:
The diagonals of a rhombus ...... each other at ...... angles.
ABCD is a rhombus. If ∠ACB = 40°, find ∠ADB.
Construct a rhombus whose diagonals are of length 10 cm and 6 cm.
Which of the following statement is true for a rectangle?
Its diagonals are equal and bisect each other.
If the adjacent sides of a parallelogram are equal then parallelogram is a ______.
Diagonals of a quadrilateral are perpendicular to each other. Is such a quadrilateral always a rhombus? Give a figure to justify your answer.
