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The Figure Shows Two Vessels with Adiabatic Walls, One Containing 0.1 G of Helium (γ = 1.67, M = 4 G Mol−1) - Physics

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प्रश्न

The figure shows two vessels with adiabatic walls, one containing 0.1 g of helium (γ = 1.67, M = 4 g mol−1)  and the other containing some amount of hydrogen (γ = 1.4, M = 2 g mol−1). Initially, the temperatures of the two gases are equal. The gases are electrically heated for some time during which equal amounts of heat are given to the two gases. It is found that the temperatures rise through the same amount in the two vessels. Calculate the mass of hydrogen.

संक्षेप में उत्तर
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उत्तर

Given:
Mass of He, mHe = 0.1 g
γ1 = 1.67
Molecular weight of He, MHe = 4 g/mol
MH2 = ?
MH2 = 2 g/mol
γ2 = 1.4
Since it is an adiabatic environment and the system is not dong any external work, the amount of heat given will be used up entirely to raise its internal energy.
For He, dQ = dU = nCvdT   ...(i)

`= "m"/4 xx "R"/(gamma-1) xx "d""T"`

`= 0.1 /4 xx "R"/((1.67 -1)) xx "d""T"`

For H2dQ =dU = nCvdT   ...(ii)

=`"m"/2 xx "R"/(gamma-1) xx "d""T"`

=`"m"/2 xx "R"/(1.4-1) xx "d""T"`

where m is the required mass of H2.
Since equal amount of heat is given to both gases; so dQ is same in both eq (i) and (ii), we get

`0.1/4 xx "R"/0.67""d""T"`

`= "m"/2 xx "R"/0.4 xx"d""T"`

`= m = 0.1/2 xx 0.4 /0.67`

`=> m =0.0298 ≈ 0.03 "g"`

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अध्याय 5: Specific Heat Capacities of Gases - Exercises [पृष्ठ ७९]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 5 Specific Heat Capacities of Gases
Exercises | Q 28 | पृष्ठ ७९

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

Given below are densities of some solids and liquids. Give rough estimates of the size of their atoms:

Substance Atomic Mass (u) Density (10Kg m-3)
Carbon (diamond) 12.01 2.22
Gold 197.00 19.32
Nitrogen (liquid) 14.01 1.00
Lithium 6.94 0.53
Fluorine (liquid) 19.00 1.14

[Hint: Assume the atoms to be ‘tightly packed’ in a solid or liquid phase, and use the known value of Avogadro’s number. You should, however, not take the actual numbers you obtain for various atomic sizes too literally. Because of the crudeness of the tight packing approximation, the results only indicate that atomic sizes are in the range of a few Å].


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