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The Equation Y = a Sin 2 ( K X − ω T ) Represents a Wave Motion with

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प्रश्न

The equation \[y = A   \sin^2   \left( kx - \omega t \right)\] 
represents a wave motion with 

विकल्प

  • amplitude A, frequency \[\omega/2\pi\]

  • amplitude A/2, frequency \[\omega/\pi\]

  • amplitude 2A, frequency \[\omega/4\pi\]

  • does not represent a wave motion.

MCQ
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उत्तर

amplitude A/2, frequency \[\omega/\pi\]
\[y = A \sin^2 \left( kx - \omega t \right)\]

\[\left[ \cos^2 \theta = 1 - 2 \sin^2 \theta \sin^2 \theta = \frac{1 - \cos^2 \theta}{2} \right]\]

\[y = A\left[ \frac{1 - \cos^2 \left( kx - \omega t \right)}{2} \right]\] 

\[y = \frac{A}{2}\left[ 1 - \cos^2 \left( kx - \omega t \right) \right]\]
Thus, we have:
Amplitude = \[\frac{A}{2}\] 
\[2\left( \frac{\omega}{2\pi} \right) = \frac{\omega}{\pi}\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 15: Wave Motion and Waves on a String - MCQ [पृष्ठ ३२२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 15 Wave Motion and Waves on a String
MCQ | Q 4 | पृष्ठ ३२२

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