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The density of iron crystal is 8.54-gram cm–3. If the edge length of the unit cell is 2.8 A° and atomic mass is 56 gram mol–1

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प्रश्न

The density of iron crystal is 8.54-gram cm–3. If the edge length of the unit cell is 2.8 A° and atomic mass is 56 gram mol–1, find the number of atoms in the unit cell.  (Given: Avogadro's number = 6.022x1023,1A° = 1x10-8 cm)

संख्यात्मक
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उत्तर

Given a = 2.8Å = `2.8 xx 10^(-8)` cm

Molar Mass = 56 gm

Density = 8.54 g cm-3

Volume = (a)3

`= (2.8 xx 10^(-8))^3`

`= 21.95 xx 10^(-24) cm^3`

Density of unit cell = `"Mass of unit cell"/"Volume of unit cell"`

∴ Mass of unit cell = density x volume

`= 21.95 xx 10^(-24) xx 8.54`

`= 187.47 xx 10^(-24)`

56 gm of Fe contains 6.022 x 1023 atoms

`187.47 xx 10^(-24)` gm Fe contain = `(6.022xx10^23 xx 187.47xx10^(-24))/56`

= `20.15xx 10^(-1)`

= 2.01

= 2

Number of atoms in unit cell is 2.

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2017-2018 (March)

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