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The Condition of Air in a Closed Room is Described as Follows. Temperature = 25°C, Relative Humidity = 60%, Pressure = 104 Kpa. If All the Water Vapour is Removed - Physics

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प्रश्न

The condition of air in a closed room is described as follows. Temperature = 25°C, relative humidity = 60%, pressure = 104 kPa. If all the water vapour is removed from the room without changing the temperature, what will be the new pressure? The saturation vapour pressure at 25°C − 3.2 kPa.

योग
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उत्तर

Here , 

T = 298 K

RH = 60%

`"P" = 1.04 xx 10^5  "Pa"`

RH = `"Vapour pressure of water vapour" /"saturated Vapour pressure"`

=0.6

`"Saturated vapour pressure"= 3.2 xx 10^3  "Pa"`

⇒`"vapour pressure of water vapour"  ("VP") = 0.6 xx 3.2 xx 10^3 = 1.92 xx 10^3  "Pa"`

If the water vapour is completely removed from the air , then net pressure = `1.04 xx 10^5 - 1.92 xx 10^3`

=`1.02 xx 10^5 "Pa"`

=102 kPa

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अध्याय 2: Kinetic Theory of Gases - Exercises [पृष्ठ ३७]

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एचसी वर्मा Concepts of Physics Vol. 2 [English] Class 11 and 12
अध्याय 2 Kinetic Theory of Gases
Exercises | Q 47 | पृष्ठ ३७

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