Advertisements
Advertisements
प्रश्न
The angles of a quadrilateral are 110°, 72°, 55° and x°. Find the value of x.
Advertisements
उत्तर
\[\text{ The sum of anlges of a quadilateral is } 360°. \]
\[\text{ So, we get } 110° + 72° + 55° + x = 360° \]
\[ \Rightarrow 237°+ x = 360° \]
\[ \Rightarrow x = 360° - 237° \]
\[ \therefore x = 123° \]
APPEARS IN
संबंधित प्रश्न
In Fig. 16.19, ABCD is a quadrilateral.
How many pairs of opposite angles are there?

In a convex hexagon, prove that the sum of all interior angle is equal to twice the sum of its exterior angles formed by producing the sides in the same order.
In ΔABC, E is the mid-point of median AD such that BE produced meets AC at F. IF AC = 10.5 cm, then AF =
Use the information given in the following figure to find :
(i) x
(ii) ∠B and ∠C

Angle A of an isosceles trapezium ABCD is 115°; find the angles B, C and D.
Write two conditions that will make the adjoining figure a square.

Observe the figure below and find out their name.

A pair of opposite sides of a trapezium are ______.
In the following figure,

∠AOE is a/an ______ angle
Using the information given, name the right angles in part of figure:
RT ⊥ ST

