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प्रश्न
The abscissa of a point is positive in the
विकल्प
First and Second quadrant
Second and Third quadrant
Third and Fourth quadrant
Fourth and First quadrant
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उत्तर
The signs of coordinates (x , y) of a point in various quadrants are shown in the following graph:
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संबंधित प्रश्न
Find the third vertex of a triangle, if two of its vertices are at (−3, 1) and (0, −2) and the centroid is at the origin.
The line segment joining A( 2,9) and B(6,3) is a diameter of a circle with center C. Find the coordinates of C
In what ratio does the point C (4,5) divides the join of A (2,3) and B (7,8) ?
If A(3, y) is equidistant from points P(8, −3) and Q(7, 6), find the value of y and find the distance AQ.
If the vertices of a triangle are (1, −3), (4, p) and (−9, 7) and its area is 15 sq. units, find the value(s) of p.
If the centroid of the triangle formed by points P (a, b), Q(b, c) and R (c, a) is at the origin, what is the value of a + b + c?
The distance between the points (a cos θ + b sin θ, 0) and (0, a sin θ − b cos θ) is
Find the coordinates of the point which lies on x and y axes both.
If the points P(1, 2), Q(0, 0) and R(x, y) are collinear, then find the relation between x and y.
Given points are P(1, 2), Q(0, 0) and R(x, y).
The given points are collinear, so the area of the triangle formed by them is `square`.
∴ `1/2 |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)| = square`
`1/2 |1(square) + 0(square) + x(square)| = square`
`square + square + square` = 0
`square + square` = 0
`square = square`
Hence, the relation between x and y is `square`.
Assertion (A): The ratio in which the line segment joining (2, -3) and (5, 6) internally divided by x-axis is 1:2.
Reason (R): as formula for the internal division is `((mx_2 + nx_1)/(m + n) , (my_2 + ny_1)/(m + n))`
