हिंदी

Tan-1 sqrt3 - cot-1 (-sqrt3) is equal to ______.

Advertisements
Advertisements

प्रश्न

`tan^-1 sqrt3 - cot^-1 (- sqrt3)` is equal to ______.

विकल्प

  • π

  • `-pi/2`

  • 0

  • `2 sqrt3`

MCQ
रिक्त स्थान भरें
Advertisements

उत्तर

`tan^-1 sqrt3 - cot^-1 (- sqrt3)` is equal to `underlinebb(-pi/2)`.

Explanation:

⇒ `tan^-1 sqrt3 - cot^-1 (- sqrt3)`

= `tan^-1 (tan  pi/3) - cot^-1 (-cot  pi/6)`

= `pi/3 - cot^-1 [cot (pi - pi/6)]`

= `pi/3 - cot^-1 [cot ((5pi)/6)]`

= `pi/6 - (5 pi)/6`

= `(2pi - 5pi)/6`

= `-(3pi)/6`

= `- pi/2`

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

संबंधित प्रश्न

Prove that: `tan^(-1)(1/2)+tan^(-1)(1/5)+tan^(-1)(1/8)=pi/4`


If `tan^-1(2x)+tan^-1(3x)=pi/4`, then find the value of ‘x’.


Prove the following:

3 sin−1 x = sin−1 (3x − 4x3), `x ∈ [-1/2, 1/2]`


Write the following function in the simplest form:

`tan^(-1) ((3a^2 x - x^3)/(a^3 - 3ax^2)), a > 0; (-a)/sqrt(3) < x < a/sqrt(3)`


`sin[pi/3 - sin^(-1) (-1/2)]` is equal to ______.


Prove that `sin^(-1)  8/17 + sin^(-1)  3/5 = tan^(-1)  77/36`.


Prove `tan^(-1)   1/5 + tan^(-1)  (1/7) + tan^(-1)  1/3 + tan^(-1)  1/8 = pi/4`


Prove `(9pi)/8 - 9/4  sin^(-1)  1/3 = 9/4 sin^(-1)  (2sqrt2)/3`


Solve for x : \[\tan^{- 1} \left( \frac{x - 2}{x - 1} \right) + \tan^{- 1} \left( \frac{x + 2}{x + 1} \right) = \frac{\pi}{4}\] .


If cos-1 x + cos -1 y + cos -1 z = π , prove that x2 + y2 + z2 + 2xyz = 1.


If y = `(x sin^-1 x)/sqrt(1 -x^2)`, prove that: `(1 - x^2)dy/dx = x + y/x`


Find: ∫ sin x · log cos x dx


Find the value, if it exists. If not, give the reason for non-existence

`sin^-1 [sin 5]`


Find the value of the expression in terms of x, with the help of a reference triangle

sin (cos–1(1 – x))


Find the value of `sin^-1[cos(sin^-1 (sqrt(3)/2))]`


If tan–1x + tan1y + tan1z = π, show that x + y + z = xyz


Simplify: `tan^-1  x/y - tan^-1  (x - y)/(x + y)`


Choose the correct alternative:

If |x| ≤ 1, then `2tan^-1x - sin^-1  (2x)/(1 + x^2)` is equal to


Prove that `2sin^-1  3/5 - tan^-1  17/31 = pi/4`


Prove that `tan^-1 ((sqrt(1 + x^2) + sqrt(1 - x^2))/((1 + x^2) - sqrt(1 - x^2))) = pi/2 + 1/2 cos^-1x^2`


Prove that `sin^-1  8/17 + sin^-1  3/5 = sin^-1  7/85`


If 3 tan–1x + cot–1x = π, then x equals ______.


The value of the expression `tan (1/2 cos^-1  2/sqrt(5))` is ______.


The number of real solutions of the equation `sqrt(1 + cos 2x) = sqrt(2) cos^-1 (cos x)` in `[pi/2, pi]` is ______.


If y = `2 tan^-1x + sin^-1 ((2x)/(1 + x^2))` for all x, then ______ < y < ______.


The minimum value of sinx - cosx is ____________.


`"cot" (pi/4 - 2  "cot"^-1  3) =` ____________.


The value of expression 2 `"sec"^-1  2 + "sin"^-1 (1/2)`


The value of the expression tan `(1/2  "cos"^-1 2/sqrt3)`


The value of `"tan"^-1 (1/2) + "tan"^-1(1/3) + "tan"^-1(7/8)` is ____________.


The value of `"tan"^-1 (3/4) + "tan"^-1 (1/7)` is ____________.


If `"tan"^-1 2  "x + tan"^-1 3  "x" = pi/4`, then x is ____________.


`"cos" (2  "tan"^-1 1/7) - "sin" (4  "sin"^-1 1/3) =` ____________.


If `6"sin"^-1 ("x"^2 - 6"x" + 8.5) = pi,` then x is equal to ____________.


If `3  "sin"^-1 ((2"x")/(1 + "x"^2)) - 4  "cos"^-1 ((1 - "x"^2)/(1 + "x"^2)) + 2 "tan"^-1 ((2"x")/(1 - "x"^2)) = pi/3` then x is equal to ____________.


The Government of India is planning to fix a hoarding board at the face of a building on the road of a busy market for awareness on COVID-19 protocol. Ram, Robert and Rahim are the three engineers who are working on this project. “A” is considered to be a person viewing the hoarding board 20 metres away from the building, standing at the edge of a pathway nearby. Ram, Robert and Rahim suggested to the firm to place the hoarding board at three different locations namely C, D and E. “C” is at the height of 10 metres from the ground level. For viewer A, the angle of elevation of “D” is double the angle of elevation of “C” The angle of elevation of “E” is triple the angle of elevation of “C” for the same viewer. Look at the figure given and based on the above information answer the following:

Measure of ∠EAB = ________.


The Simplest form of `cot^-1 (1/sqrt(x^2 - 1))`, |x| > 1 is


The value of cosec `[sin^-1((-1)/2)] - sec[cos^-1((-1)/2)]` is equal to ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×