हिंदी

Find: ∫ Sin X · Log Cos X Dx

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प्रश्न

Find: ∫ sin x · log cos x dx

योग
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उत्तर

`∫  sin "x" ·log  cos"x"  "dx"`

Substitute cos x = t

sinx dx = dt

`∫ - "log t  dt"`

= - (t log t - t ) + C

= - t log t + t + C

= - cos x log (cos x )+ cos x + C

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2018-2019 (March) 65/1/3

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