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प्रश्न
Find the value of `sin^-1[cos(sin^-1 (sqrt(3)/2))]`
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उत्तर
`sin^-1[cos(sin^-1 (sqrt(3)/2))] = sin^-1 [cos pi/3]`
= `sin^-1 [1/2]`
= `pi/6`
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