हिंदी
तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएचएससी विज्ञान कक्षा १२

Choose the correct alternative: If |x| ≤ 1, then 2tan-1x-sin-1 2x1+x2 is equal to - Mathematics

Advertisements
Advertisements

प्रश्न

Choose the correct alternative:

If |x| ≤ 1, then `2tan^-1x - sin^-1  (2x)/(1 + x^2)` is equal to

विकल्प

  • tan–1x

  • sin1x

  • 0

  • π

MCQ
Advertisements

उत्तर

0

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 4: Inverse Trigonometric Functions - Exercise 4.6 [पृष्ठ १६८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 4 Inverse Trigonometric Functions
Exercise 4.6 | Q 16 | पृष्ठ १६८

संबंधित प्रश्न

 
 
 

Prove that `tan^(-1)((6x-8x^3)/(1-12x^2))-tan^(-1)((4x)/(1-4x^2))=tan^(-1)2x;|2x|<1/sqrt3`

 
 
 

 

Prove that:

`tan^(-1)""1/5+tan^(-1)""1/7+tan^(-1)""1/3+tan^(-1)""1/8=pi/4`

 

Write the function in the simplest form: `tan^(-1)  1/(sqrt(x^2 - 1)), |x| > 1`


Write the following function in the simplest form:

`tan^(-1) (sqrt((1-cos x)/(1 + cos x)))`, 0 < x < π


Write the following function in the simplest form:

`tan^(-1) ((3a^2 x - x^3)/(a^3 - 3ax^2)), a > 0; (-a)/sqrt3 < x < a/sqrt3`


Find the value of the given expression.

`tan(sin^(-1)  3/5 + cot^(-1)  3/2)`


`sin[pi/3 - sin^(-1) (-1/2)]` is equal to ______.


Find the value, if it exists. If not, give the reason for non-existence

`sin^-1 (cos pi)`


Find the value of the expression in terms of x, with the help of a reference triangle

`tan(sin^-1(x + 1/2))`


Prove that `tan^-1x + tan^-1  (2x)/(1 - x^2) = tan^-1  (3x - x^3)/(1 - 3x^2), |x| < 1/sqrt(3)`


Choose the correct alternative:

`tan^-1 (1/4) + tan^-1 (2/9)` is equal to


If |x| ≤ 1, then `2 tan^-1x + sin^-1 ((2x)/(1 + x^2))` is equal to ______.


The number of real solutions of the equation `sqrt(1 + cos 2x) = sqrt(2) cos^-1 (cos x)` in `[pi/2, pi]` is ______.


The value of cot–1(–x) for all x ∈ R in terms of cot–1x is ______.


`"tan"^-1 1/3 + "tan"^-1 1/5 + "tan"^-1 1/7 = "tan"^-1 1/8 =` ____________.


If `"tan"^-1 (("x" - 1)/("x" + 2)) + "tan"^-1 (("x" + 1)/("x" + 2)) = pi/4,` then x is equal to ____________.


`"tan"^-1 1/3 + "tan"^-1 1/5 + "tan"^-1 1/7 + "tan"^-1 1/8 =` ____________.


The value of `"cos"^-1 ("cos" ((33pi)/5))` is ____________.


`"tan"^-1 (sqrt3)`


`sin^-1(1 - x) - 2sin^-1 x = pi/2`, tan 'x' is equal to


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×